Compare Quantity A and Quantity B, using additional information centered above the two quantities if such information is given, and select one of the following four answer choices:

(A) Quantity A is greater.

(B) Quantity B is greater.

(C) The two quantities are equal.

(D) The relationship cannot be determined from the information given.

(A) Quantity A is greater.

(B) Quantity B is greater.

(C) The two quantities are equal.

(D) The relationship cannot be determined from the information given.

N = 1323*1325*1327*1329

Quantity A : Rem[N/13] + 1

Quantity B : Rem[N/11]

where Rem[A/B] is defined as the remainder obtained when A is divided by B.

Correct Answer: C

### Explanation

The solution to this question becomes very simple with the understanding of a simple concept involving remainders.

If N = x1 * x2 * x3 * ……… * xn

And if Rem[x1/k] = r1

Rem[x2/k] = r2 and so on…..

Then, Rem[N/k] = Rem[(r1 * r2 * r3* ………..* rn)/k]

This can be continued recursively until we are left with a single remainder.

Now, in this question, N = 1323*1325*1327*1329

Quantity A: k = 13

Therefore, Rem[1323/13] = 10

Rem[1325/13] = 12

Rem[1327/13] = 1

Rem[1329/13] = 3

Hence, Rem[N/13] = Rem[(10*12*1*3)/13]

= Rem[360/13]

= 9

Similarly, Quantity B: k = 11

Therefore, Rem[1323/11] = 3

Rem[1325/11] = 5

Rem[1327/11] = 7

Rem[1329/11] = 9

Hence, Rem[N/11] = Rem[(3*5*7*9)/11]

= Rem[945/11]

= 10

Or, to illustrate how this can be used recursively,

Rem[N/11] = Rem[(3*5*7*9)/11]

= Rem{[Rem(27/11)*Rem(35/11)]/11}

= Rem{[5*2]/11}

= Rem[10/11]

= 10

## Questions, answers, comments welcome