When four is added to six times a number and the result squared, the result obtained is four times the square of the sum of the number and its next multiple. What is the number?

**Explanation:**

The question can be directly converted to an equation as follows.

Let ‘n’ be the number.

(4 + 6n)

^{2}= 4(n + 2n)^{2}2

^{2}(2 + 3n)^{2}= 4(3n)^{2}4 + 12n + 9n

^{2}= 9n^{2}
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