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You are here: Home / GRE Quant / Geometry / Solid Geometry Mensuration – Circles

Solid Geometry Mensuration – Circles

November 23, 2012 By K S Baskar Leave a Comment

Chord AC at a distance of 7 cm from the center of a circle subtends an angle of 120 degrees at the center. Find the area of major segment.

Answer: 1232/3 + 49*root(3)

Explanation:

GRE Practice Geometry Circles Major Segment
In triangle OCD,
Angle (COD) = 60 degrees
Angle (OCD) = 30 degrees
Hence tan(OCD) = OD/CD
CD = 7*root(3)
Sin(OCD) = OD/OC
OC = 14
Hence AC = 14*root(3)
Area of triangle AOC = (1/2)*AC*OD
                                         = (1/2)*14*root(3)*7
                                         = 49*root(3)
Area of sector AOC(reflex angle) = (240/360)*pi*14*14
                                                                 = 1232/3
Area of major segment = Area of sector AOC(reflex) + Area of triangle AOC
                                             = 1232/3 + 49*root(3)

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