Find the 50th term of the following series:
1 + 3 + 7 + 13 + 21 + …………
1 + 3 + 7 + 13 + 21 + …………
Answer: 2451
Explanation
t2 – t1= 2 (2*1)
t3 – t2= 4 (2*2)
t4 – t3 = 6 (2*3)
………………………..
…………………………
………………………..
t50 – t49= 98 (2*49)
Adding all the equations, we get
t50 – t1= 2 + 4 + 6 + ………. + 98
t50 – t1= 2450
t50 – 1 = 2450
Therefore, t50 = 2451
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