This GRE® quant practice question tests your understanding of properties of triangles in Geometry. Concepts tested include properties of right triangles, orthocenter and circumcenter of triangles. Also, basic properties of coordinate geometry including coordinates of mid point of a line segment, equation of a line, computing intercepts of a line and distance between two points are tested in this question.
- 12 units
- 10 units
- 5 units
- 7 units
- 14 units
Consider the diagram below where the line 4x + 3y = 24 forms a triangle with the coordinate axes.
How to determine the points where the line cuts the x and y axes?
So, the line cuts the x-axis at (6, 0)
The line therefore, cuts the y-axis at (0, 8)
Where is the orthocenter of a right triangle located?
Thus, orthocenter for this triangle lies at (0, 0).
Where is the circumcenter of a right triangle located?
The circumcenter of any triangle is the point of intersection of the 3 perpendicular bisectors of the triangle. The circumcenter is the center of the circle that circumscribes the triangle.
Thus, mid-point of the segment joined by the points (6, 0) and (0, 8) is the circumcenter of this triangle.
The coordinates of the mid point of (6, 0) and (0, 8) = (, ) = (3, 4)
Thus, the distance between (0, 0) and (3, 4) is the distance between the orthocenter and circumcenter of this triangle.
Distance between (0, 0) and (3, 4) = = 5 units.
The line joining the orthocenter and the circumcenter is nothing but the median to the hypotenuse.
The orthocenter is one of the vertices of the triangle. The circumcenter is the mid-point of the opposite side. A line from a vertex to the mid point of the opposite side is the median to that side.
We know that the median to the hypotenuse is the circumradius.
The distance between the center of a circle to any point on its circumference will measure the radius of the circle. The 3 vertices of the triangle lie on the circumference of the circumcircle. So, the distance between the circumcenter and any of the 3 vertices will be the same and will be equal to the circumradius.
Hence, 5 units.
I will leave that part for you to figure out.